Armstrong Number

Codenya:

import java.util.Scanner;

class ArmstrongNumber
{
   public static void main(String args[])
   {
      int n, sum = 0, temp, remainder, digits = 0;

      Scanner in = new Scanner(System.in);
      System.out.println("Input a number to check if it is an Armstrong number");    
      n = in.nextInt();

      temp = n;

      // Count number of digits

      while (temp != 0) {
         digits++;
         temp = temp/10;
      }

      temp = n;

      while (temp != 0) {
         remainder = temp%10;
         sum = sum + power(remainder, digits);
         temp = temp/10;
      }

      if (n == sum)
         System.out.println(n + " is an Armstrong number.");
      else
         System.out.println(n + " is not an Armstrong number.");        
   }

   static int power(int n, int r) {
      int c, p = 1;

      for (c = 1; c <= r; c++)
         p = p*n;

      return p;  
   }
}


Hasilnya: